What is the output of the following program
main()
{
int a=10;
int b=6;
if(a=3)
b++;
printf("%d %dn",a,b++);
}
a)
10,6
b)
10,7
c)
3,6
d)
3,7
e)
none
Correct answer is option 'D'. Can you explain this answer?

Question

What is the output of the following programmain(){int a=10;int b=6;if(a=3)b++;printf("%d %dn",a,b++);}a)10,6b)10,7c)3,6d)3,7e)noneCorrect answer is option 'D'. Can you explain this answer?

Answer

Here 'a' is assigned with value of 3. to check we just need to compare '==' instead '='.

Answer

There is a syntax error in the program as the printf statement is incomplete. The correct program should be:

#include

int main(){
int a = 10;
int b = 6;
if(a = 3)
b;
printf('%d', b);
return 0;
}

The output of this program is 6, as the if statement assigns the value 3 to variable a (due to the single equals sign used for assignment instead of comparison), but does not execute the b statement. Therefore, the value of b remains unchanged at 6, which is then printed to the console.

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